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$\displaystyle {\textstyle\frac{3}{4}}$x + $\displaystyle {\textstyle\frac{5}{6}}$ = 5x - $\displaystyle {\textstyle\frac{125}{3}}$
12$\displaystyle \left(\vphantom{\frac{3}{4}x+\frac{5}{6}}\right.$$\displaystyle {\textstyle\frac{3}{4}}$x + $\displaystyle {\textstyle\frac{5}{6}}$$\displaystyle \left.\vphantom{\frac{3}{4}x+\frac{5}{6}}\right)$ = 12$\displaystyle \left(\vphantom{5x-\frac{125}{3}}\right.$5x - $\displaystyle {\textstyle\frac{125}{3}}$$\displaystyle \left.\vphantom{5x-\frac{125}{3}}\right)$
12$\displaystyle \left(\vphantom{\frac{3}{4}x}\right.$$\displaystyle {\textstyle\frac{3}{4}}$x$\displaystyle \left.\vphantom{\frac{3}{4}x}\right)$ + 12$\displaystyle \left(\vphantom{\frac{5}{6}}\right.$$\displaystyle {\textstyle\frac{5}{6}}$$\displaystyle \left.\vphantom{\frac{5}{6}}\right)$ = 12(5x) - 12$\displaystyle \left(\vphantom{\frac{125}{3}}\right.$$\displaystyle {\textstyle\frac{125}{3}}$$\displaystyle \left.\vphantom{\frac{125}{3}}\right)$
3(3x) + 2(5) = 60x - 500
 
9x + 10 = 60x - 500
 
10 = 51x - 500
 
510 = 51x
 
x = $\displaystyle {\textstyle\frac{510}{51}}$ = 10
المعادلة الثانية
 

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